Optimal. Leaf size=262 \[ \frac{x \left (a+b x^3\right )^{5/3} \left (a^2 d^2-6 a b c d+27 b^2 c^2\right )}{162 b^2}+\frac{5 a x \left (a+b x^3\right )^{2/3} \left (a^2 d^2-6 a b c d+27 b^2 c^2\right )}{486 b^2}-\frac{5 a^2 \left (a^2 d^2-6 a b c d+27 b^2 c^2\right ) \log \left (\sqrt [3]{a+b x^3}-\sqrt [3]{b} x\right )}{486 b^{7/3}}+\frac{5 a^2 \left (a^2 d^2-6 a b c d+27 b^2 c^2\right ) \tan ^{-1}\left (\frac{\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}+1}{\sqrt{3}}\right )}{243 \sqrt{3} b^{7/3}}+\frac{d x \left (a+b x^3\right )^{8/3} (15 b c-4 a d)}{108 b^2}+\frac{d x \left (a+b x^3\right )^{8/3} \left (c+d x^3\right )}{12 b} \]
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Rubi [A] time = 0.164922, antiderivative size = 262, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {416, 388, 195, 239} \[ \frac{x \left (a+b x^3\right )^{5/3} \left (a^2 d^2-6 a b c d+27 b^2 c^2\right )}{162 b^2}+\frac{5 a x \left (a+b x^3\right )^{2/3} \left (a^2 d^2-6 a b c d+27 b^2 c^2\right )}{486 b^2}-\frac{5 a^2 \left (a^2 d^2-6 a b c d+27 b^2 c^2\right ) \log \left (\sqrt [3]{a+b x^3}-\sqrt [3]{b} x\right )}{486 b^{7/3}}+\frac{5 a^2 \left (a^2 d^2-6 a b c d+27 b^2 c^2\right ) \tan ^{-1}\left (\frac{\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}+1}{\sqrt{3}}\right )}{243 \sqrt{3} b^{7/3}}+\frac{d x \left (a+b x^3\right )^{8/3} (15 b c-4 a d)}{108 b^2}+\frac{d x \left (a+b x^3\right )^{8/3} \left (c+d x^3\right )}{12 b} \]
Antiderivative was successfully verified.
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Rule 416
Rule 388
Rule 195
Rule 239
Rubi steps
\begin{align*} \int \left (a+b x^3\right )^{5/3} \left (c+d x^3\right )^2 \, dx &=\frac{d x \left (a+b x^3\right )^{8/3} \left (c+d x^3\right )}{12 b}+\frac{\int \left (a+b x^3\right )^{5/3} \left (c (12 b c-a d)+d (15 b c-4 a d) x^3\right ) \, dx}{12 b}\\ &=\frac{d (15 b c-4 a d) x \left (a+b x^3\right )^{8/3}}{108 b^2}+\frac{d x \left (a+b x^3\right )^{8/3} \left (c+d x^3\right )}{12 b}+\frac{\left (27 b^2 c^2-6 a b c d+a^2 d^2\right ) \int \left (a+b x^3\right )^{5/3} \, dx}{27 b^2}\\ &=\frac{\left (27 b^2 c^2-6 a b c d+a^2 d^2\right ) x \left (a+b x^3\right )^{5/3}}{162 b^2}+\frac{d (15 b c-4 a d) x \left (a+b x^3\right )^{8/3}}{108 b^2}+\frac{d x \left (a+b x^3\right )^{8/3} \left (c+d x^3\right )}{12 b}+\frac{\left (5 a \left (27 b^2 c^2-6 a b c d+a^2 d^2\right )\right ) \int \left (a+b x^3\right )^{2/3} \, dx}{162 b^2}\\ &=\frac{5 a \left (27 b^2 c^2-6 a b c d+a^2 d^2\right ) x \left (a+b x^3\right )^{2/3}}{486 b^2}+\frac{\left (27 b^2 c^2-6 a b c d+a^2 d^2\right ) x \left (a+b x^3\right )^{5/3}}{162 b^2}+\frac{d (15 b c-4 a d) x \left (a+b x^3\right )^{8/3}}{108 b^2}+\frac{d x \left (a+b x^3\right )^{8/3} \left (c+d x^3\right )}{12 b}+\frac{\left (5 a^2 \left (27 b^2 c^2-6 a b c d+a^2 d^2\right )\right ) \int \frac{1}{\sqrt [3]{a+b x^3}} \, dx}{243 b^2}\\ &=\frac{5 a \left (27 b^2 c^2-6 a b c d+a^2 d^2\right ) x \left (a+b x^3\right )^{2/3}}{486 b^2}+\frac{\left (27 b^2 c^2-6 a b c d+a^2 d^2\right ) x \left (a+b x^3\right )^{5/3}}{162 b^2}+\frac{d (15 b c-4 a d) x \left (a+b x^3\right )^{8/3}}{108 b^2}+\frac{d x \left (a+b x^3\right )^{8/3} \left (c+d x^3\right )}{12 b}+\frac{5 a^2 \left (27 b^2 c^2-6 a b c d+a^2 d^2\right ) \tan ^{-1}\left (\frac{1+\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}}{\sqrt{3}}\right )}{243 \sqrt{3} b^{7/3}}-\frac{5 a^2 \left (27 b^2 c^2-6 a b c d+a^2 d^2\right ) \log \left (-\sqrt [3]{b} x+\sqrt [3]{a+b x^3}\right )}{486 b^{7/3}}\\ \end{align*}
Mathematica [C] time = 4.8714, size = 176, normalized size = 0.67 \[ \frac{x \left (a+b x^3\right )^{2/3} \left (-9 b x^3 \text{Gamma}\left (-\frac{2}{3}\right ) \left (c+d x^3\right )^2 \text{HypergeometricPFQ}\left (\left \{-\frac{2}{3},\frac{4}{3},2\right \},\left \{1,\frac{13}{3}\right \},-\frac{b x^3}{a}\right )-3 b x^3 \text{Gamma}\left (-\frac{2}{3}\right ) \left (11 c^2+16 c d x^3+5 d^2 x^6\right ) \, _2F_1\left (-\frac{2}{3},\frac{4}{3};\frac{13}{3};-\frac{b x^3}{a}\right )+20 a \text{Gamma}\left (-\frac{5}{3}\right ) \left (14 c^2+7 c d x^3+2 d^2 x^6\right ) \, _2F_1\left (-\frac{5}{3},\frac{1}{3};\frac{10}{3};-\frac{b x^3}{a}\right )\right )}{252 \text{Gamma}\left (\frac{1}{3}\right ) \left (\frac{b x^3}{a}+1\right )^{2/3}} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.22, size = 0, normalized size = 0. \begin{align*} \int \left ( b{x}^{3}+a \right ) ^{{\frac{5}{3}}} \left ( d{x}^{3}+c \right ) ^{2}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.7733, size = 1713, normalized size = 6.54 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 14.9286, size = 270, normalized size = 1.03 \begin{align*} \frac{a^{\frac{5}{3}} c^{2} x \Gamma \left (\frac{1}{3}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{2}{3}, \frac{1}{3} \\ \frac{4}{3} \end{matrix}\middle |{\frac{b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac{4}{3}\right )} + \frac{2 a^{\frac{5}{3}} c d x^{4} \Gamma \left (\frac{4}{3}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{2}{3}, \frac{4}{3} \\ \frac{7}{3} \end{matrix}\middle |{\frac{b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac{7}{3}\right )} + \frac{a^{\frac{5}{3}} d^{2} x^{7} \Gamma \left (\frac{7}{3}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{2}{3}, \frac{7}{3} \\ \frac{10}{3} \end{matrix}\middle |{\frac{b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac{10}{3}\right )} + \frac{a^{\frac{2}{3}} b c^{2} x^{4} \Gamma \left (\frac{4}{3}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{2}{3}, \frac{4}{3} \\ \frac{7}{3} \end{matrix}\middle |{\frac{b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac{7}{3}\right )} + \frac{2 a^{\frac{2}{3}} b c d x^{7} \Gamma \left (\frac{7}{3}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{2}{3}, \frac{7}{3} \\ \frac{10}{3} \end{matrix}\middle |{\frac{b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac{10}{3}\right )} + \frac{a^{\frac{2}{3}} b d^{2} x^{10} \Gamma \left (\frac{10}{3}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{2}{3}, \frac{10}{3} \\ \frac{13}{3} \end{matrix}\middle |{\frac{b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac{13}{3}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b x^{3} + a\right )}^{\frac{5}{3}}{\left (d x^{3} + c\right )}^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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